I am tryin to solve it, plz help me yaar
solve it using the Variable Separable Form:
y (2 log y + 1) dy= (Sinx + xCosx) dx
solve it using the Variable Separable Form:
y (2 log y + 1) dy= (Sinx + xCosx) dx
How to solve this Differential Equation problem??
integrate both sides..its vry easy..u dnt have to do nething..
thnx, such a silly of me...
aree i m gettin stuck in the middle, u plz solve it for me naa...
aree i m gettin stuck in the middle, u plz solve it for me naa...
Integrate the RHS directly... For the LHS put y=e^t.. so log y =t
H
ans is
2logy+2((y*y)logy-(y*y)) = xsinx
2logy+2((y*y)logy-(y*y)) = xsinx