Logic needed... decimal numbers

9 posts · originally from https://geek.digit.in/community/threads/logic-needed-decimal-numbers.91719/

I need some help with VB coding.
I need to split the decimal part of a number and use it later. eg.input is 10.88, splitted to say num1=10 and num2=88 .
Can someone help me with the logic here.

suppose num=xx.yy
then
digit=0; // no of digits after decimal
num1=(int)num;
while(num!=(int)num)
digit++;
num2=num-num1*(10^digit);

//so num=num1.num2 now

Thanks Pathik
Code looks good for c/c++, however i am not sure how exactly i can implement it in VB ? any help here

try referring to this link, this is what u want:
*www.developerfusion.co.uk/show/5957/3/

Nope. Don't know VB at all. Wait for the others.

Hmmm. eveb I don't know VB. But I can think of some logic:
1. Convert the number into string.
2. Split the string using '.' as sperator
3. Convert the split parts into integers again and use them.

Well i know VB..

Which VB are u using..
VB 6 or latest version..?

Yeah theres a way...

get the floor function from *www.dreamincode.net/code/snippet178.htm

floor(10.88) = 10, it cuts down the number to the exponent(number before the dot) only.

To get the mantissa(number after the dot) subtract the floor value from the original number.

10.88 - floor(10.88) = 10.88 - 10 = 0.88

and multiply it by 100 to get 88, which is your num2.

so simply,

num1 = floor(10.88)
num2 = (10.88 - num1)* 100

dheeraj_kumar said:
Yeah theres a way...

get the floor function from *www.dreamincode.net/code/snippet178.htm

floor(10.88) = 10, it cuts down the number to the exponent(number before the dot) only.

To get the mantissa(number after the dot) subtract the floor value from the original number.

10.88 - floor(10.88) = 10.88 - 10 = 0.88

and multiply it by 100 to get 88, which is your num2.

so simply,

num1 = floor(10.88)
num2 = (10.88 - num1)* 100

Seems to be working... Thanks dheeraj_kumar
@adi... its vb6